Diketahui fungsi f(x)=2x+1 dan (f0g)(x)=-2x²-4x-1 nilaig(-2)=

(f o g) (x) = -2x² – 4x – 1
2 g(x) + 1 = -2x² – 4x – 1
2 g(x) = -2x² – 4x – 1 – 1
g(x) = (-2x² – 4x – 2)/2
g(-2) = – (-2)² – 2 . (-2) – 1
g(-2) = -4 + 4 – 1
g(-2) = -1

Mapel : Matematika
Kelas : 10
Materi : Bab 3 Fungsi
Kata Kunci : Fungsi Komposisi
Kode Soal : 2
Kode Kategorisasi : 10.2.3