Diketahui fungsi f(x)=px+q.Jika f(4)=19 dan f(11)=47,nilai f(-2) adalah…..

Jawaban:

f(-2) = -23

Penjelasan dengan langkah-langkah:

f(x) = px + q

f(4) = 19 —> 19 = 4p + q

f(11) = 47 —> 47 = 11p + q

—————–. –

-28 = -4p

p = 7

substitusi p = 7 ke 4p + q = 19

4(7) + q = 19

28 + q = 19

q = 19 – 28

q = -9

f(x) = px + q

f(x) = 7x – 9

f(-2) = 7(-2) – 9

= -14 – 9

= -23

semoga membantu