Diketahui fungsi linier f dengan f(–2) = 8 dan f(3) = –7. Rumus fungsi f(x – 2) adalah ….​

❐ Fungsi

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f(-2) = -2a + b = 8

f(3) = 3a + b = -7

Eliminasi b

f(3) – f(-2) = -7 – 8

3a + b – (-2a + b) = -15

5a = -15

a = -3

Tentukan nilai b

3a + b = -7

3(-3) + b = -7

-9 + b = -7

b = 2

Rumus fungsi

f(x) = ax + b

f(x) = -3x + 2

Rumus fungsi f(x – 2)

f(x) = -3x + 2

f(x – 2) = -3(x – 2) + 2

f(x – 2) = -3x + 6 + 2

f(x – 2) = -3x + 8