Diketahui f(x )= x + 2 g(x) = 4 – 3x dan h(x)= 2x + 3 jika (f o g o h)-¹ a = 1 nilai dari a =

goh (x) = g (h(x))

= 4 – 3 h(x)

= 4 – 3 (2x + 3)

= 4 – 6x – 9

= -6x – 5

fogoh (x) = f (goh(x))

= goh(x) + 2

= -6x – 5 + 2

= -6x – 3

Bila mencari invers, misalkan fungsi yg akan diinvers dulu, lalu cari nilai x

misalkan fogoh (x) = p

fogoh (x) = -6x – 3

p = – 6x – 3

6x = – p – 3

x = (- p – 3)/6

(fogoh)^-1 (x) = (-x-3)/6

(fogoh)^-1 (a) = 1

(-a – 3)/6 = 1

-a – 3 = 1 × 6

-a – 3 = 6

– a = 6 + 3

-a = 9

a = -9