Diketahui f(x)=x+1 dan g(x)=x²-6, nilai dari (fog)(4) adalah

f(x) = (x + 1)

g(x) = (x² – 6)

(fog)(x) = f(g(x))

(fog)(x) = f(x² – 6)

(fog)(x) = (x² – 6) + 1

(fog)(x) = x² – 6 + 1

(fog)(x) = x² – 5

(fog)(4) = (4)² – 5

(fog)(4) = 16 – 5

(fog)(4) = 11