Diketahui nilai g(x)=2x-1 dan (fog)(x)=4x^2-6x+10. nilai f(3)=

(fog)(x) = f(g(x)

4x² – 6x + 10 = f(2x – 1)

f(x) = (fog)(g⁻¹(x))

    = 4[(x + 1)/2]² – 6[(x + 1)/2] + 10

    = 4[(x² + 2x + 1)/4] – 3(x + 1) + 10

    = x² + 2x + 1 – 3x – 3 + 10

    = x² – x + 8

f(x) = x² – x + 8

f(3) = 3³ – 3 + 8

      = 9 – 3 + 8

      = 14

Semoga Membantu

#F

g(x)=2x-1

(fog)(x)=4x^2-6x+10.

f{ g(x)}= 4x^2-6x+10.

f(2x – 1) = 4x^2-6x+10

untuk f(3) = …

misalkan 2x – 1 = 3

2x = 4

x = 2

sub x = 2  ke 4x^2-6x+10

f(3)  = 4(2)^2 – 6(2) + 10

f(3) = 16 -12 + 10

f(3) = 14