Diketahui persamaan garis x+2y = 4 ditranslasikan t (2 1), tentukan bayangan garis tersebut​

[x' , y'] = [x + 2 , y + 1]

x =x' – 2

y =y' – 1

(x' – 2) + 2 ( y' – 1) = 4

x – 2 + 2y – 2 = 4

x + 2y – 8 = 0

Penjelasan dengan langkah-langkah:

x + 2y = 4

a = 2, b = 1

(x – a) + 2(y – b) = 4

(x – 2) + 2(y – 1) = 4

x + 2y – 2 – 2 – 4 = 0

x + 2y – 8 = 0