Diketahui segitiga ABC lancip dengan AB = 2√2, BC = 2, dan ∠ABC = 0. jika sin 0 = 1 per 3, panjang AC = . . . .
Jawaban Terkonfirmasi
Sin O = 1/3
cos O = √( 1- sin² O) = √( 1- 1/9)= √(8/9) = 2/3 √2
AC² = BC² + AB² – 2 (BC)(AB) cos O
AC² = 4 + 8 – 2(2)(2√2)(2/3)(√2)
AC² = 4 + 8 – 32/3 = 12 – 32/3 = (36-32)/3 = 4/3
AC = √4 /√3 = 2/3 √3