diketahui sin a⁰= 3/5 dan 90⁰<a<180⁰ hitunglah csc a⁰ + cot (180-a)⁰ dan tan ( 180 + a )⁰ + csc (630+ a)⁰​

Jawab:

#dirumahsajalah

sin a = 3/5 , a di kuadran II

cos a = – 4/5

tan a = – 3/4

csc a + cot (180- a) =  1/sin  a –  tan a

=  5/3 +  3/4 = 29/12

tan (180 + a) + csc (630 + a) =

= – tan a – csc a

=  3/4 – 1/sin a

= 3/4 – 5/3

=  - 11/12