Diketahui sin A=0,75 cos B=0,8 ,jika sudut A dan B sudut lancip, tentukan nilai dari cos A sin B
Jawaban Terkonfirmasi
Bab Trigonometri
Matematika SMA Kelas X
sin A = 0,75 = 3/4 = y/r
tripel pitagoras
x = √(r² – y²)
x = √(4² – 3²)
x = √(16 – 9)
x = √7
cos B = 0,8 = 4/5 = x/r
tripel pitagoras
y = √(r² – x²)
y = √(5² – 4²)
y = √(25 – 16)
y = 3
cos A . sin B
= (√7)/4 . 3/5
= (3/20) √7
CosA = 1/sinA = 1/0,75
= 1/75/100 -> 1/1 x 100/75 = 4/3
sinB = 1/cosB = 1/0,8 = 1/8/10 = 1/1 x 10/8 = 10/8 = 5/4