Diketahui sinyal analog : x_a (t)=3cos⁡〖2000πt+5 sin 6000πt+10 cos⁡1200πt 〗 Hitung Nyquist rate Bila Fs = 500 Hz, cari x[n]

Jawaban: Fs = 500 Hz

Xa(t) = 3 cos (1000 * 2pi ) + 5 sin (3000 * 2pi) + 10 cos(600 *2pi)

X(n) = Xa(nT)

X(n) = 3 cos (1000/Fs *2pi)n + 5 sin (3000/fs *2pi)n + 10 cos(600/fs *2pi)n

X(n) = 3 cos 4pi n + 5 sin 12pi n + 10 cos 2.4pi n

Penjelasan: X(n) = Xa (nT)