Diketahui SPLDV 3×+2y=2 dan ×-4y=10 nilai×+y adalah​

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Diketahui SPLDV 3×+2y=2 dan ×-4y=10 nilai×+y adalah​

Penjelasan dengan langkah-langkah:

SPLDV

3x + 2y = 2 (A)

x – 4y = 10 (B)

Eliminasi y

(4A) -> 12x + 8y = 8

(2B) -> 2x – 8y = 20

============ +

14x = 28

x = 2

(A) 3 . 2 + 2y = 2

6 + 2y = 2

2y = 2 – 6

2y = -4

y = -2

x + y

= 2 + (-2)

= 0

Detail Jawaban

Mapel – Matematika

Kode Soal – 2

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