Diketahui suatu fungsi f(x) = ax + 7. Jika f(3) = 1, Nilai dari f(1) adalah ?

F(x)=ax+7
f(3)=1
3a+7 = 1
3a = 1-7 = -6
a = -6/3
a = -2

f(x) = -2x + 7
f(1) = -2(1) + 7 = -2+7 = 5

Qed

F(3) = 3a +7 = 1
3a = -6
a = -2
F(1) = (1)(-2) + 7 =
-2 + 7 = 5