Diketahui system persamaan 4x-3y=1 dan 2x-y= -3 maka nilai 3x-2y adalah

4x – 3y = 1
2x – y = – 3 { x3 }

4x – 3y = 1
6x – 3y = – 9
__________ +
10x = 8
x = 8/10

4x – 3y = 1
16/5 – 3y = 1
– 3y = 1 – 16/5
– 3y = 5/5 – 16/5
– 3y = – 11/5
– y = – 11/5 × 3
– y = – 33/5
y = 33/5

3x – 2y
24/10 – 66/5
2,4 – 13,2
– 10,8

2x-y=-3
y=2x+3

dimasukan
4x-3(2x+3)=1
4x-6x-6=1
-2x=7
x= -3,5

4x-3y=1
4.(-3.5)-3y=1
-14-3y=1
y= -5

3x-2y =3.(-3,5)-2.(-5)
=-0,5