Diketahui vektor a = 2,21 vektor

B = 6,2, -3 tentukanlah nilai sinus sudut antara vektor a dan b

Diketahui vektor a = 2,21 vektor

$cos(x) = frac{a.b}{ |a| |b| } \$

$|a| = sqrt{ {2}^{2} + {2}^{2} + {1}^{2} } = 3 \ |b| = sqrt{ {6}^{2} + {2}^{2} + {( - 3)}^{2} } = 7$

$a.b = (2 times 6) + (2 times 2) + (1 times ( - 3) = 13$

$cos(x) = frac{a.b}{ |a| |b| } \ \ cos(x) = frac{13}{7 times 3} = frac{13}{21} ≈51.8°$