Diketahui vektor a = 3ndan b = -2-3 Jika 2a +3b =03 maka carilah harga n .

Diketahui vektor a = 3ndan b = -2-3 Jika 2a +3b =03 maka carilah harga n .

Jawab:

$a=left[begin{array}{ccc}3 \n \ end{array}right] \b=left[begin{array}{ccc}-2 \-3 \ end{array}right] \dimana\2a+3b=left[begin{array}{ccc}0 \ 3 \ end{array}right]\2left[begin{array}{ccc}3 \n \ end{array}right]+3left[begin{array}{ccc}-2 \-3 \ end{array}right] =left[begin{array}{ccc}0 \ 3 \ end{array}right]\left[begin{array}{ccc}6 \2n \ end{array}right]+ left[begin{array}{ccc}-6 \-9 \ end{array}right] =left[begin{array}{ccc}0 \ 3 \ end{array}right]$

$left[begin{array}{ccc}6-6 \ 2n-9 \ end{array}right]=left[begin{array}{ccc}0\ 3 \ end{array}right]\left[begin{array}{ccc}0 \ 2n-9 \ end{array}right]=left[begin{array}{ccc}0\ 3 \ end{array}right]$

$2n-9=3\2n=3+9\2n=12\n=6$

jadi, nilai n adalah 6