Diketahui:h(x) = |x-5|nilai dari h(0)+ (5) -h(10) x h (-2)​mohon dibantu

Penjelasan:

h(0)=(0-5)

= -5

h(5) = (5-5)

= 0

h(10) = (10-5)

=5

h(-2) = (-2-5)

= -7

h(0)+h(5)-h(10)×h(-2) =

-5 + 0 – 5 × -7 =

-5 +0 +35 = 30