Dik=fungsi y=-6×2+24+-19Tentukan A. Sumbu simetri B. Nilai optimum C. Titik optimum

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Dik=fungsi y=-6×2+24+-19Tentukan A. Sumbu simetri B. Nilai optimum C. Titik optimum

a = - 6 \ b = 24 \ c = - 19 \ \ a.sumbu : simetri \ x = frac{b}{a} = - frac{24}{ - 6} = 4 \ \ b.nilai : optimum \ yo = - frac{ {b}^{2} - 4ac}{4a} \ : : : : : = - frac{(24) ^{2} - 4( - 6)( - 19) }{4( - 6)} \ : : : : = - frac{576 - 456}{ - 24} \ : : : = - frac{120}{24} \ : : : = 5 \ \ c.titik : optimum \ = (x,y) \ = (4,5)

Y = -6x² + 24x – 19

a) x = -b/2a

x = -24/2(-6)

x = -24/-12

x = 2

b) y = D/-4a

y = (24²- 4(-6)(-19))/-4(-6)

y = ( 576 – 456)/24

y = 120/24

y = 5

c) tik.mum ( x , y )

= ( 2, 5 )