Dua benda masing-masing 4 µC (micro Coulomb ) dan 8 µC, satu sama lain berjarak 20 Cm berada di udara. Hitung besar gaya tolak-menolak kedua benda tersebut!

#tolong bantu jawab

Dua benda masing-masing 4 µC (micro Coulomb ) dan 8 µC, satu sama lain berjarak 20 Cm berada di udara. Hitung besar gaya tolak-menolak kedua benda tersebut!

Jawaban:

diket :

1μC = 1×10^-6C
4μC = 4×10^-6C
8μC = 8×10^-6C
k = 9×10⁹ Nm²/C²
r = 20 cm = 2 × 10^-1m

ditanya:

gaya tolak menolak (F)…?

jawab

$f = k frac{q1q2}{ {r}^{2} }$

$f = (9 times {10}^{9}) frac{(4 times 10 {}^{ - 6})(8 times {10}^{ - 6}) }{(2 times {10}^{ - 1}) {}^{2} }$

$f = (9 times {10}^{9}) frac{(32 times {10}^{ - 12}) }{(4 times {10}^{ - 2}) }$

$f = (9 times {10}^{9})(8 times {10}^{ - 10})$

$f = 72 times {10}^{ - 1} n$

Jawaban:

dik :

q1 = 4micro coulomb = 4 x 10^-6 coloumb

q2 = 8micro coulomb = 8 x 10^-6 coloumb

r = 20 cm = 20 x 10^-2 m

$fcoloumb = frac{k times q1 times q2}{ {r}^{2} } \ = frac{9 times {10}^{9} times 4 times {10}^{ - 6} times 8 times {10}^{ - 6} }{ {(20 times {10}^{ - 2} })^{2} } \ = frac{288 times {10}^{ - 3} }{ {20}^{2} times {10}^{ - 4 } } \ = frac{288 times {10}^{ - 3} }{400 times {10}^{ - 4} } \ = 0.72 times 10 \ = 7.2 : newton$

Penjelasan:

smg membantu:)