Dua buah dadu merah dan biru dilemparkan bersama sama.hitunglah peluang munculnya:

N(s) = (1,1) (1,2) (1,3)……….(6,6)
= 36

a.Mata dadu uo 5
n(a) = (1,4) (2,3) (3,4) (4,1)
= 4
p(a) = n(a) / n(s)
= 4/36
=1/8

b.Mata dadu lebih dari 5

n(s) = (1,5) (1,6) (2,4) (2,5) (2,6) (3,3) (3,4) (3,5) (3,6) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) = 25

p(a) = n(a)/n(s)
= 25/36

c.dadu merah ganjil
n(s) = *(merah,biru)
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) = 18

p(a) = n(a)/n(s)
= 18/36
=1/2

d.kedua mata dadu prima
n(s) = (1,1) (1,3) (1,5) (3,1) (3,3) (3,5) (5,1) (5,3) (5,5) = 9

p(a) = n(a)/n(s)
=9/36
=1/4

e.jumlah kedua mata dadu ganjil

n(s)= (1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5) = 18

p(a) = n(a)/n(s)
= 18/36
= 1/2

f.merah = genap
biru = prima
n(s) = (merah,biru)
(2,1) (2,3) (2,5) (4,1) (4,3) (4,5) (6,1) (6,3) (6,5) = 9

p(a)= n(a)/n(s)
= 9/36
= 1/4

n

A. 4/36 = 1/9

B. 6/36 = 1/6

C. 6/36 = 1/6

D. 6/36 = 1/6

E. 18/36 = 2/4 =1/2

F. 3/36 × 3/36 = 1/12 × 1/12
= 1/144

semoga membantu, maaf kalau ada kesalahan ^^