Duah buah kapasitor masing-masing 20 f dan 10f dihubungkan dengan beda potensial 50 volt Hitunglah muatan dan energi pada kapasitor tersebut jika:

Jawaban:

C1 =20F

C2= 10F

V= 50v

Cseri = C1 + C2 = 20+ 10 = 30 F

1/Cparalel = 1/C1 + 1/C2

1/Cp =1/20 + 1/10

1/Cp = 1/20 + 2/20

1/Cp =3/20

Cp = 20/3

a. Wseri = 1/2 CsV²

 Ws =1/2 x 30 x (50)²

 Ws= 37500 J

 W= 1/2 QV

2W= QV

Q= 2W/V

Qseri = 2Ws / V

 =2 x 37500 / 50

 = 1500 C

b. Wp = 1/2 CpV²

 = 1/2 x 20/3 x(50)²

 = 8333,333 J

 Qp = 2Wp/V

 = 2 x 8333,333/ 50

 = 333,333 C