F(2 – x) = 3x + 4f(2) = …​

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F(2 – x) = 3x + 4f(2) = …​

f(2 – x) = 3x + 4

f(2) = …

2 – x = a

-x = a – 2

x = -a + 2

f(2) = 3(-2 + 2) + 4

f(2) = 3(0) + 4

f(2) = 0 + 4

f(2) = 4

🙂

Penjelasan dengan langkah-langkah:

f(2 – x) = 3x + 4

f(2 – 2) = 3(2 – 2) + 4

f(2 – 2) = 6 – 6 + 4

f(2 – 2) = 0 + 4

f(2 – 2) = 4