F(4x-1)=16x^2-12x+17, f(x) berapa?

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F(4x-1)=16x^2-12x+17, f(x) berapa?

Jawaban:

Diketahui:

  • f(4x – 1) = 16x² – 12x + 17

Ditanya

  • f(x) ?

Jawab:

f(4x – 1) = 16x² – 12x + 17

misal

  • (4x – 1) = k
  • 4x = k + 1
  • x = (k + 1) / 4

masukkan

f(k) = 16[(k + 1)/4]² – 12[(k + 1) / 4) + 17

f(k) = 16[(k² + 2k + 1) / 16] – 3(k + 1) + 17

f(k) = (k² + 2k + 1) – 3k – 3 + 17

f(k) = k² + 2k – 3k + 1 – 3 + 17

f(k) = k² – k + 15

ganti jadi x

f(x) = x² – x + 15

Kesimpulan

  • Jadi, nilai f(x) adalah x² – x + 15

Detail jawaban

♬ Mapel : Matematika

♬ Kelas : X

♬ Materi : Bab 3 – Fungsi

♬ Kode mapel : 2

♬ Kode kategorisasi : 10.2.3

♬ Kata kunci : Nilai f(x)

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