Faktor kan bentuk bentuk kuadrat berikut ini =

Penjelasan dengan langkah-langkah:

a. n² – 5n – 6 = 0

a = 1, b = -5, c = – 6

a × c = – 6

1 × (-6) = -6

1 + (-6) = -5

n² + n – 6 n – 6 = 0

(n² + n) – (6n + 6) = 0

n(n + 1) – 6(n + 1) = 0

(n – 6)(n + 1) = 0

b. a² + 2a = 63

a² + 2a – 63 = 0

a = 1, b = 2, c = -63

a × c = …

1 × (-63) = -63

9 + ( -7 ) = 2

a² + 9a – 7a – 63 = 0

(a² + 9a) – (7a + 63) = 0

a(a + 9) – 7(a + 9) = 0

(a – 7)(a + 9) = 0

c. x² – 16 = 0

a = 1, b = 0, c = – 16

a × c = …

1 × (-16) = 16

-4 + 4 = 0

x² – 4x + 4x – 16 = 0

(x² – 4x) + (4x – 16) = 0

x(x – 4) + 4(x – 4) = 0

(x + 4)(x – 4) = 0

Jawaban:

a. (n+1)(n-6)

b. a²+2a-63=0

(a+9)(a-7)

c. (x+4)(x-4)