Faktor persamaan m² + 1 m – 12= 0
Jawab:
(1 – m)x² + (8 – 2m)x + 12 = 0
akar kembar –> D = 0
b² – 4ac = 0
(8-2m)² – 4.(1-m).12 = 0
64 – 32m + 4m² – 48 + 48m = 0
4m² + 16m + 16 = 0
m² + 4m + 4 = 0
(m + 2)² = 0
m + 2 = 0
m = -2.
Penjelasan dengan langkah-langkah: