a.4x² – 12x + 9
b.3x² + 3x – 6
c.2x² – 5x – 3
Tolong, pake caranya ya,, terimakasih banyak..
Faktorkan:
B. 3x^2 + 3x – 6 = 0 (dibagi 3)
= x^2 + x – 2
= (x + 2)(x – 1)
x1 : x + 2 = 0
x = -2
x2 : x – 1 = 0
x = 1
A. 4x^2-12x+9
(2x-3) (2x-3)
2x-3= 0 2x-3
2x= 3 2x= 3
x= 3/2 x=3/2
b.3x^2+3x-6
(3x-3) (x+2)
3x-3 = 0 x+2 = 0
3x = 3 x = -2
x = 3/3
x = 1
c. 2x^2-5x-3
(2x+1) (x-3)
2x+1= 0 x-3= 0
2x= -1 x= 3
x= -1/2