Fungsi F oleh f(x)=ax+b jika bayangan -3=15 dan bayangan 3=9 tentukan nilai dari f(-2)+f(2)

– f(x)=ax+b
f(-3) = a(-3)+b
-15 = a(-3)+b
-15 = -3a+b
– f(x)=ax+b
f(3) = a(3)+b
f(3) = 3a+b
-3a+b= -15
3a+b = 9 (dikurang)
-6a = -24
a = -24 : -6
a = 4
3a+b = 9
3(4)+b =9
12+b =9
b = 9-12
b = -3
f(x) = ax+b
f(x) = 4x-3
f(-2) = 4(-2)-3
f(-2) = -8-3
f(-2) = -11
f(2) = 4(2)-3
f(2) = 8-3
f(2) = 5
Jadi, f(-2)+f(2) = -11 + 5 = -6