Fungsi f(x) = 5 – 6x – x^2 dapat dinyatakan dalam bentuk f(x) = -(x+p)^2 + q. Nilai p dan q berturut-turut adalah…

-x²-6x+5
= -(x²+6x-5)
= -(x²+6x+9-9-5)
= -(x²+3)²+(9+5)
= -(x²+3)²+14

maka p=3, q=14

F(x) = 5 – 6x – x²
-(x² + 6x – 5) = 0
a = 1
b = 6
c = 5

c = (b/2)² = (6/2)² = 3² = 9

-(x² + 6x + 5 + 4) = 4
-(x² + 3) -4 = 0
p = 3
q = -4