Fungsi h di tentukan oleh h (x) = ax + b, jika h (2) = 13 dan h (5) = 22, nilai h (-3) + h (0) adalah

Penjelasan dengan langkah-langkah:

h (x) = ax + b

h (2) = 13

2a + b = 13

h (5) = 22

5a + b = 22

5a + b = 22

2a + b = 13

—————– –

3a = 9

a = 9/3

a = 3

2a + b = 13

2 . 3 + b = 13

6 + b = 13

b = 13 – 6

b = 7

h (x) = 3x + 7

h (-3) = 3 . (-3) + 7

h (-3) = -9 + 7

h (-3) = -2

h (0) = 3 . 0 + 7

h (0) = 7

h (-3) + h (0)

= -2 + 7

= 5

Detail Jawaban

Kelas 8

Mapel 2 – Matematika

Bab 2 – Fungsi

Kode Kategorisasi : 8.2.2

Jawaban:

nilai h(-3) + h (0) = 5

Penjelasan dengan langkah-langkah:

Subtitusi

22 = 5a + b

13 = 2a + b –

9 = 3a

a = 9/3

a = 3

Eliminasi

2a + b = 13

2(3) + b = 13

6 + b = 13

b = 13 – 6 = 7

Nilai h(-3) + h (0)

h (x) = ax + b

h (-3) = 3(-3) + (7)

h (-3) = -9 + 7

h (-3) = -2

h (x) = ax + b

h (0) = 3(0) + (7)

h (0) = 0 + 7

h (0) = 7

-2 + 7 = 5