Fungsi kuadrat memiliki nilai minimim-4 dan x=1 serta nilai 5 x=4 adalah
Jawaban Terkonfirmasi
Xmin = 1
Ymin = – 4
Xmin = 1
-b / 2a = 1
-b = 2a
b = – 2a
Ymin = – 4
( b^2 – 4ac) / – 4a = – 4
( (-2a)^2 – 4ac) = 16a
4a^2 – 4ac = 16a
4a(a – c) = 16a
a – c = 4
c = a – 4
Untuk x = 4, y = 5, maka
Y = ax^2 + bx + c
5 = a(4)^2 + 4b + c
5 = 16a + 4b + c
5 = 16a + 4(-2a) + a-4
5 = 16a – 8a + a – 4
9 = 9a
a = 1
b = – 2a = – 2(1) = – 2
c = a – 4 = 1 – 4 = – 3
F(x) = ax^2 + bx + c
F(x) = x^2 – 2x – 3
Semoga membantu 😀