F(x) = (1/3)2√3^(2x+1) By Admin ReiPosted on December 5, 2022 F(x) = (1/3)2√3^(2x+1) = 2/3 3pangkat(2x+1)pangkat1/2=2/3 3pangkat(x +1/2)=2pangkat(x+1/2)