F(x-1)=2x+3 g(x) =5x-2 dan h(x)=2x^2+7. Rumus fungsi (fogoh) (x)=

(f o g o h)(x) = f(g(h(x)))

g(h(x)) = g (2x²+7)
⇔ 5(2x²+7) – 2
⇔ 10x² + 35 -2
⇔ 10x² + 33

f(g(h(x))) = f(10x²+33)
⇔ 2(10x²+33) +3
⇔ 20x² + 66 + 3
⇔20x² + 69

jadi rumus fungsi (f o g o h)(x) = 20x² + 69