F(x) = 2x pangkat 2 – 3x + 1 Tentukan • f(2) • f(-3)

F(x) = 2x^2 – 3x + 1

* f(2) = 2(2)^2 – 3(2) + 1

= 8 – 6 + 1

= 1

* f(-3) = 2(-3)^2 – 3(-3) + 1

= 18 – (-9) + 1

= 28

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