F(x) = 2x² + 2(fof)(1) = ?​

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F(x) = 2x² + 2(fof)(1) = ?​

Diketahui :

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  • f(x) = 2x² + 2

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Ditanya :

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  • (fof)(1) = ?

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Penyelesaian :

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(fof)(1)

= 2(2(1)²+2)² +2

= 2(2.1+2)² + 2

= 2(2+2)² + 2

= 2(4)² + 2

= 2.16 + 2

= 32 + 2

= 34

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Kesimpulan :

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  • (fof)(1) = 34

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Fungsi Komposisi

Fungsi komposisi: memasukkan fungsi yang satu ke suatu fungsi yang lain.

Diketahui f(x) = 2x^2 + 2

Maka (f~ o ~ f)(1) :

(f~ o ~ f)(x) = f(f(x))

(f~ o ~ f)(x) = 2f^2 (x) + 2

(f~ o ~ f)(x) = 2(2x^2 + 2)^2 + 2

(f~ o ~ f)(x) = 2(4x^4 + 8x^2 + 4) + 2

(f~ o~ f)(x) = 8x^4 + 16x^2 + 8 + 2

large red{sf{(f~ o ~ f)(x) = 8x^4 + 16x^2 + 10}}

large red{sf{(f~ o~ f)(1) = 8(1)^4 + 16(1)^2 + 10}}

large red{sf{(f~ o~ f)(1) = 8 + 16 + 10}}

large red{sf{(f~ o ~ f)(1) = 34}}