F(x) = 8x² + = ... - Universityku

F(x) = 8x² + = …

Jawab:

$largetext{$begin{aligned}&dfrac{df(x)}{dx}=bfdfrac{1+sqrt[bf3]{bf x^5}}{sqrt[bf3]{bf x^2}}end{aligned}$}$

PEMBAHASAN

Turunan

$largetext{$begin{aligned}Biggl.f(x)&=8x^2+sqrt[3]{x}end{aligned}$}$

$largetext{$begin{aligned}Biggl.frac{df(x)}{dx}&=frac{d}{dx}left(8x^2+sqrt[3]{x}right)\Biggl.&=8cdotfrac{d}{dx}left(x^2right)+frac{d}{dx}left({x}^{{}^{1}!!/!{}_{3}}right)\Biggl.&=8cdot2x+frac{1}{3}x^{-{}^{2}!!/!{}_{3}}\Biggl.&=16x+frac{1}{3x^{{}^{2}!!/!{}_{3}}}\Biggl.&=frac{48x^{left(1+{}^{2}!!/!{}_{3}right)}+1}{3x^{{}^{2}!!/!{}_{3}}}\Biggl.&=frac{1+48x^{{}^{5}!!/!{}_{3}}}{3x^{{}^{2}!!/!{}_{3}}}end{aligned}$}$

$largetext{$begin{aligned}frac{df(x)}{dx}&=bfdfrac{1+sqrt[bf3]{bf x^5}}{sqrt[bf3]{bf x^2}}end{aligned}$}$