F(x)= sin x-cos x/sin x, tentukan f'(1/3π)mohon bantuannya ka​

~ Turunan Fungsi Trigono

f(x) = (sin x – cos x) / sin x

f'(x) = [(cos x + sin x).sin x – (sin x – cos x).cos x) / sin²x

f'(x) = (cos x . sin x + sin²x – cos x . sin x + cos²x) / sin²x

f'(x) = (sin² x + cos² x) / sin² x

f'(x) = csc² x

Maka :

f'(π/3) = csc² (π/3)

f'(π/3) = 4/3 ✓