F(x) = x² – 2x + 3! tentukan nilai optimum fungsi kuadrat!​

f(x) = x² – 2x + 3

a = 1

b = -2

c = 3

nilai optimum = – (b² – 4ac/4a)

= – (-2²) – 4.1.3/4.1)

= – (4 – 12/4)

= – (4 – 3)

= – (1)

= -1

jadi, nilai optimum nya -1