F(x)=3x-5, g(x)=2x²+7 f(x)=3x-5, g(x)2x²+7 rumus fungsi (fog)(x)

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F(x)=3x-5, g(x)=2x²+7
f(x)=3x-5, g(x)2x²+7 rumus fungsi (fog)(x)

Diketahui

f(x) = 3x – 5

g(x) = 2x² + 7

Hence,

(fog)(x) = f(g(x))

(fog)(x) = 3(2x² + 7) – 5

(fog)(x) = 6x² + 21 – 5

(fog)(x) = 6x² + 16