F(x)=ax²-3x+c.f(1)=4f(2)=7f(-1)=?​

Jawab:

Penjelasan dengan langkah-langkah:

fungsi

nilai fungsi

__

f(x) =  ax² – 3x + c

f(1) = 4 –> a – 3 + c= 4

f(2) = 7–> 4a – 6 + c = 7 __ (-)

-3a + 3 = – 3

-3a= – 6

a= 2

a – 3 + c= 4

2 – 3 + c= 4

-1 + c = 4

c= 5

f(x) =  ax² – 3x + c ,  a= 2, c= 5

f(-1) = 2(1) – 3(-1) + 5

f(-1) = 2 + 3 + 5

f(-1) = 10