f(x)=x2-x+2.jika diketahui Domain D=[0,1,2]maka RANGE fungsi tsb adalah…… A(2,0,4) B.(0,4) C.(2,4) D.(2) TOLONG DIJAWAB

F(x) = x^2 -x +2
f (0) = 0^2 -0 +2 = 2
f (1) = 1^2 – 1 +2 = 2
f (2) = 2^2 -2 +2 = 4
Range = { 2, 4 }

F(x) = x² – x + 2
Domain = {0, 1, 2}

f(0) = (0)² – (0) + 2 = 0 – 0 + 2 = 2
f(1) = (1)² – (1) + 2 = 1 – 1 + 2 = 2
f(2) = (2)² – (2) + 2 = 4 – 2 + 2 = 4

Range fungsi adalah {2, 4}……..Jawaban (C)