Gan…tolong bantuin saya,saya gk ngerti caranya !!

A).ab^2-ob^2
=10^2-6^2
=100-36
=64
=diakar=8 cm
B).pq=op^2-oq^2
=13^2-5^2
=169-25
=144
=12 cm

1. panjang AB = √10²-6²
= √100-36
= √64
= 8 cm

2. a. panjang PQ= √13²+5²
= √169-25
= √144
= 12 cm
b.
= ½× 5cm× 12cm
= 1/2× 60cm
= 30 cm²