Gas propana dalam kurung c3h 8 tutup kurung, diketahui Delta H derajat F = negatif 104 kj​

Penjelasan:

C3H8 + 5 023 CO2 + 4 H2O

a. ΔΗ = [3 ΔΗ°CO2 + 4 ΔΗ°f H2O] – [ΔΗ°f

C3H8 + 5 AH°f 02]

= [(3 x – 393,5) + (4 × – 285,8)] – [- 104

+ (5 × 0)]

– 2219,7 kJ/mol = -2219700 J/mol

==

b. AH = -(Q = mol)

– 2219700 = -((m × c × At) ÷ (mol)) – 2219700 = -((5000 × 4,2 × 45) = mol) mol = 0,425

gr = mol x Mr

= 0,425 × 44

= 18,73 gr