a. 2x² – x – 6
b. 2x² + x – 6
c. 2x² + 7x – 6
d. 2x² – 7x – 6
Gd yg mo cp :v ma sy
Jawaban:
~Aljabar
(2x + 3)(x – 2)
= (2x × x) – (2x × 2) + (3 × x) – (3 × 2)
= 2x² + 4x + 3x – 6
= 2x² – 7x – 6 (A)
» Aljabar
(2x + 3)(x – 2)
= (2x)(x) – (2x)(2) + (3)(x) – (3)(2)
= 2x² – (2x)(2) + (3)(x) – (3)(2)
= 2x² – 4x + (3)(x) – (3)(2)
= 2x² – 4x + 3x – 6
= 2x² + (-4 + 3)x – 6
= 2x² + (-1)x – 6
= 2x² – x – 6