Grafik fungsi y = -3x² + nx + 1 mencapai nilai maksimum di titik (p, 1 1/3). Tentukan nilai n dan p?
Jawaban Terkonfirmasi
Y = -3x^2 + nx + 1
max (p, 1 1/3)
y max = b^2-4ac/-4a
1 1/3 = (n^2-4*(-3)*1)/-4*(-3)
4/3 = (n^2+12)/12
48/3 = n^2+12
16 = n^2 + 12
4 = n^2
n = ±2
jika n = 2:
x max = -b/2a
p = -2/2*(-3)
p = -2/-6
p = 1/3
jika n = -2:
x max = -b/2a
p = -(-2)/2*(-3)
p = 2/-6
p = -1/3