Guyss tolongin pliss sama caranya, poinnya gw tambahin

Jawaban:

1) • x²-2x = 6-x

x² – x – 6 = 0

( x+ 2 ) ( x – 3 ) = 0

x = -2 (M) x = 3 (M)

• x²-2x = 1

x² -2x-1 = 0 (TM)

• x² -2x +1 = 0

(x-1)(x-1) = 0

x= 1(M) x = 1 (M)

syarat g(x) dan h(x) harus sama sama genap atau ganjil

g(x) = x²-2x = -1

h(x) = 6-x = 7

• x²-2x=0

x(x-2) =0

x =0(TM) x = 2 ( M)

syarat g(x) dan h(x) sama sama positif

g(0) = 0-2 = -2

g(2) = 4-4 = 0

h(0) = 6-0 = 6

h(2) = 6-2 = 4

HP { -2,1,2,3}

2) • 2x -6 = 0

2 x = 6

x = 3 (M)

syarat g(x) ≠ h(x)

8(3)+2 ≠ 3-7(3)

26 ≠ -18

• g(x) = h(x)

8x+2 = 3-7x

15x = 1

x = 1/15 ( M)

HP { 1/15, 3 }

3) misal 2^x = y

2y² + y – 3 = 0

( y -1 ) ( 2y +3 ) = 0

y = 1 y = -3/2

2^x = 1. 2^x = -3/2 ( tidak memenuhi)

2^x = 2^0

x = 0 (memenuhi)

HP { x=0}