Hasil dari integral x akar2x+1 dx

InTegraL

Misal :
u = 2x + 1 —> x = 1/2 (u – 1)
du/dx = 2
dx = 1/2 du

••
∫x√(2x + 1) dx
= ∫1/2 (u – 1)u^1/2 . 1/2 du
= 1/4 ∫(u^3/2 – u^1/2) du
= 1/4 (1/(5/2) u^5/2 – 1/(3/2) u^3/2) + C
= 1/4 (2/5 u² √u – 2/3 u√u) + C
= 1/10 u² √u – 1/6 u√u + C
= (1/10 (2x + 1)² – 1/6 (2x + 1)) (√(2x + 1)) + C

Diperkecil jadi x/3 (2x+1)^3/2
U nya diganti kesemula

dijadikan akar jadi

X/3 √(2X+1)³