Hasil dari integral(x³+2) / √x⁴+8x-1 dx =…beserta caranya​

Integral

∫ax^n dx = a/(n + 1) x^(n + 1) + C

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d(x⁴ + 8x – 1)/dx = 4x³ + 8

4(x³ + 2) dx = d(x⁴ + 8x – 1)

∫(x³ + 2)√(x⁴ + 8x – 1) dx

= 1/4 ∫(x⁴ + 8x – 1)^1/2 d(x⁴ + 8x – 1)

= 1/4 . 2/3 (x⁴ + 8x – 1)^3/2 + C

= 1/6 (x⁴ + 8x – 1)^3/2 + C