Hasil integral ∫³ (x + 2) ( x – 1 ) dx =
Int 3(x + 2)((x – 1) dx
= int 3(x² + x – 2) dx
= int 3x² + 3x – 6
= 3/3 x³ + 3/2 x² – 6x + c
= x³ + 3/2x² – 6x + c
= 1/2 x (2x² + 3x – 12 )+ c
Semoga membantu maaf kalau salah
Hasil integral ∫³ (x + 2) ( x – 1 ) dx =
Int 3(x + 2)((x – 1) dx
= int 3(x² + x – 2) dx
= int 3x² + 3x – 6
= 3/3 x³ + 3/2 x² – 6x + c
= x³ + 3/2x² – 6x + c
= 1/2 x (2x² + 3x – 12 )+ c
Semoga membantu maaf kalau salah