[HELP] berapakah x? By Admin ReiPosted on December 6, 2022 [HELP] berapakah x? 2^{x-5} = 4^{x+3}2^{x-5} = 2^{2(x+3)}x-5 = 2(x+3)x-5 = 2x+6x-2x = 6+5-x = 11x = -11