Hi , boleh minta tolong koreksi?

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tolong koreksi ya , saya masih ragu dengan jawaban saya

f(x) = 9x – 6x + 100

f(3) + f(4) = 221 (apakah benar?)

Buktikan Jika Hasil nya 221
gunakan cara ya
cari dulu nilai f(3) nya terus f(4) nya​

Hi , boleh minta tolong koreksi?

f(x) = 9x – 6x + 100

f(3) = 9(3) – 6(3) + 100

f(3) = ( 9 × 3 ) – ( 6 × 3 ) + 100

f(3) = 27 – 18 + 100

f(3) = 9 + 100

f(3) = 109

f(4) = 9(4) – 6(4) + 100

f(4) = ( 9 × 4 ) – ( 6 × 4 ) + 100

f(4) = 36 – 24 + 100

f(4) = 12 + 100

f(4) = 112

maka

f(3) + f(4) =

= 109 + 112

= 221

Maka hasilnya 221

Gambar Jawaban

Penyelesaian

_____________________________

f(x) = 9x – 6x + 100

f(3) = 9(3) – 6(3) + 100

f(3) = (9.3) – (6.3) + 100

f(3) = 27 – 18 + 100

f(3) = 9 + 100

f(3) = 109

f(x) = 9x – 6x + 100

f(4) = 9(4) – 6(4) + 100

f(4) = (9.4) – (6.4) + 100

f(4) = 36 – 24 + 100

f(4) = 12 + 100

f(4) = 112

= f(3) + f(4)

= 109 + 112

= 221 (benar)

Gambar Jawaban